Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The value of the function f (x) = 1 + x + 
( n 2 t + 2 nt)dt, where f ′ (x) vanishes is:
Text Solution
Verified by ExpertsThe correct answer is:
D
f ′ (x) = 0
⇒ 1 + n 2 x + 2 n x = 0 ⇒ put nx = p ⇒ p 2 + 2p + 1 = 0
⇒ p = –1 ⇒ n x = –1 ⇒ x = 
⇒ f(x) = 
+ 
Let n t = z ⇒ 
⇒ dt = e z dz
∴ 
= 1 + 
+ 
= 
= 1 + 
= 1 + 
+ 
= 1 + 
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